题解 - 奇偶数判断

2
qinzhenlong LV 3 @ 2025-1-29 21:46:27

#include <bits/stdc++.h> using namespace std; int main() { int a; cin >> a; if ( a % 2 == 0 ) cout << "even"; else cout << "odd"; return 0; }
2
xiahaoxuan LV 2 @ 2025-1-20 21:16:21

#include<bits/stdc++.h> using namespace std;

int main() { long long a; cin>>a; if(a%2==0) cout<<"even"; else cout<<"odd"; return 0; }
0
linzeshi LV 4 @ 2025-1-26 15:42:39

#include<bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; if(n%2==0) cout<<"even"; else cout<<"odd"; return 0; }

3 条题解