该比赛已结束，您无法在比赛模式下递交该题目。您可以点击“在题库中打开”以普通模式查看和递交本题。

E - Cheating Amidakuji

Score : $500$ points

Problem Statement

Let us trace the path from the top of vertical bar $1$, and let the score be the number of the vertical bar we reach at the bottom.

For each $i=1,2,\dots,M$, answer the following question.

• Let $S_i$ be the score assuming that horizontal bar $i$ is erased. Find $S_i$.

Note that horizontal bars are not actually erased, so the questions are independent of each other.

Below is a more formal description of the problem. -->

You are given a sequence of length $M$ consisting of integers between $1$ and $N-1$, inclusive: $A=(A_1,A_2,\dots,A_M)$. Answer the following question for $i=1, 2, \dots, M$.

• There is a sequence $B=(B_1,B_2,\dots,B_N)$. Initially, we have $B_j=j$ for each $j$. Let us perform the following operation for $k=1, 2, \dots, i-1, i+1, \dots, M$ in this order (in other words, for integers $k$ between $1$ and $M$ except $i$ in ascending order).
  • Swap the values of $B_{A_k}$ and $B_{A_k+1}$.
• After all the operations, let $S_i$ be the value of $j$ such that $B_j=1$. Find $S_i$.

Constraints

• $2 \leq N \leq 2\times 10^5$
• $1 \leq M \leq 2\times 10^5$
• $1 \leq A_i \leq N-1\ (1\leq i \leq M)$
• All values in the input are integers.

Input

The input is given from Standard Input in the following format:

$N$ $M$

$A_1$ $A_2$ $\dots$ $A_M$

Output

Print $M$ lines. The $i$-th line $(1\leq i \leq M)$ should contain the value $S_i$ as an integer.

5 4
1 2 3 2

1
3
2
4

For $i = 2$, the operations change $B$ as follows.

• Initially, $B = (1,2,3,4,5)$.
• Perform the operation for $k=1$. That is, swap the values of $B_1$ and $B_2$, making $B = (2,1,3,4,5)$.
• Perform the operation for $k=3$. That is, swap the values of $B_3$ and $B_4$, making $B = (2,1,4,3,5)$.
• Perform the operation for $k=4$. That is, swap the values of $B_2$ and $B_3$, making $B = (2,4,1,3,5)$.

After all the operations, we have $B_3=1$, so $S_2 = 3$.

Similarly, we have the following.

• For $i=1$: performing the operation for $k=2,3,4$ in this order makes $B=(1,4,3,2,5)$, so $S_1=1$.
• For $i=3$: performing the operation for $k=1,2,4$ in this order makes $B=(2,1,3,4,5)$, so $S_3=2$.
• For $i=4$: performing the operation for $k=1,2,3$ in this order makes $B=(2,3,4,1,5)$, so $S_4=4$.

3 3
2 2 2

1
1
1

10 10
1 1 1 9 4 4 2 1 3 3

2
2
2
3
3
3
1
3
4
4