#AT2393. E - Cheating Amidakuji
E - Cheating Amidakuji
E - Cheating Amidakuji
Score : $500$ points
Problem Statement
Let us trace the path from the top of vertical bar , and let the score be the number of the vertical bar we reach at the bottom.
For each , answer the following question.
- Let be the score assuming that horizontal bar is erased. Find .
Note that horizontal bars are not actually erased, so the questions are independent of each other.
Below is a more formal description of the problem. -->
You are given a sequence of length $M$ consisting of integers between $1$ and $N-1$, inclusive: $A=(A_1,A_2,\dots,A_M)$. Answer the following question for $i=1, 2, \dots, M$.
- There is a sequence $B=(B_1,B_2,\dots,B_N)$. Initially, we have $B_j=j$ for each $j$. Let us perform the following operation for $k=1, 2, \dots, i-1, i+1, \dots, M$ in this order (in other words, for integers $k$ between $1$ and $M$ except $i$ in ascending order).
- Swap the values of $B_{A_k}$ and $B_{A_k+1}$.
- After all the operations, let $S_i$ be the value of $j$ such that $B_j=1$. Find $S_i$.
Constraints
- $2 \leq N \leq 2\times 10^5$
- $1 \leq M \leq 2\times 10^5$
- $1 \leq A_i \leq N-1\ (1\leq i \leq M)$
- All values in the input are integers.
Input
The input is given from Standard Input in the following format:
Output
Print $M$ lines. The $i$-th line $(1\leq i \leq M)$ should contain the value $S_i$ as an integer.
5 4
1 2 3 2
1
3
2
4
For $i = 2$, the operations change $B$ as follows.
- Initially, $B = (1,2,3,4,5)$.
- Perform the operation for $k=1$. That is, swap the values of $B_1$ and $B_2$, making $B = (2,1,3,4,5)$.
- Perform the operation for $k=3$. That is, swap the values of $B_3$ and $B_4$, making $B = (2,1,4,3,5)$.
- Perform the operation for $k=4$. That is, swap the values of $B_2$ and $B_3$, making $B = (2,4,1,3,5)$.
After all the operations, we have $B_3=1$, so $S_2 = 3$.
Similarly, we have the following.
- For $i=1$: performing the operation for $k=2,3,4$ in this order makes $B=(1,4,3,2,5)$, so $S_1=1$.
- For $i=3$: performing the operation for $k=1,2,4$ in this order makes $B=(2,1,3,4,5)$, so $S_3=2$.
- For $i=4$: performing the operation for $k=1,2,3$ in this order makes $B=(2,3,4,1,5)$, so $S_4=4$.
3 3
2 2 2
1
1
1
10 10
1 1 1 9 4 4 2 1 3 3
2
2
2
3
3
3
1
3
4
4
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