- 晶晶赴约会
为什么错
- 2025-1-16 16:49:37 @
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a;
cin>>a;
switch(a){
case 1 : cout<<"NO"<<endl;break;
case 2 : cout<<"YES"<<endl;break;
case 3 : cout<<"NO"<<endl;break;
case 4 : cout<<"YES"<<endl;break;
case 5 : cout<<"NO"<<endl;break;
case 6 : cout<<"YES"<<endl;break;
case 7 : cout<<"YES"<<endl;break;
}
return 0;
}
2 条评论
-
linzeshi LV 4 @ 2025-1-27 9:35:00已修改
#include<bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; if(n==1||n==3||n==5) cout<<"NO"; else cout<<"YES"; return 0; }
👍 2 -
2025-1-20 21:04:18@
-
#include <bits/stdc++.h> #include <iostream> #include <iomanip> #include <cmath> using namespace std; int main(){ int t; cin>>t; if((t==1 || t==3) || t==5){ cout << "NO"; }else{ cout << "YES"; } }
-
- 1
信息
- ID
- 435
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 3
- 标签
- (无)
- 递交数
- 114
- 已通过
- 62
- 上传者