#AT2412. Ex - Alchemy

Ex - Alchemy

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Ex - Alchemy

Score : $600$ points

Problem Statement

Takahashi has $A$ kinds of level-$1$ gems, and $10^{10^{100}}$ gems of each of those kinds.
For an integer $n$ greater than or equal to $2$, he can put $n$ gems that satisfy all of the following conditions into a cauldron to generate a level-$n$ gem in return.

  • No two gems are of the same kind.
  • Every gem's level is less than $n$.
  • For every integer $x$ greater than or equal to $2$, there is at most one level-$x$ gem.

Find the number of kinds of level-$N$ gems that Takahashi can obtain, modulo $998244353$.

Here, two level-$2$ or higher gems are considered to be of the same kind if and only if they are generated from the same set of gems.

  • Two sets of gems are distinguished if and only if there is a gem in one of those sets such that the other set does not contain a gem of the same kind.

Any level-$1$ gem and any level-$2$ or higher gem are of different kinds.

Constraints

  • $1 \leq N \leq 2 \times 10^5$
  • $1 \leq A \leq 10^9$
  • $N$ and $A$ are integers.

Input

The input is given from Standard Input in the following format:

NN AA

Output

Print the answer.


3 3
10

Here are ten ways to obtain a level-$3$ gem.

  • Put three kinds of level-$1$ gems into the cauldron.
    • Takahashi has three kinds of level-$1$ gems, so there is one way to choose three kinds of level-$1$ gems. Thus, he can obtain one kind of level-$3$ gem in this way.
  • Put one kind of level-$2$ gem and two kinds of level-$1$ gems into the cauldron.
    • A level-$2$ gem can be obtained by putting two kinds of level-$1$ gems into the cauldron.
      • Takahashi has three kinds of level-$1$ gems, so there are three ways to choose two kinds of level-$1$ gems. Thus, three kinds of level-$2$ gems are available here.
    • There are three kinds of level-$2$ gems, and three ways to choose two kinds of level-$1$ gems, so he can obtain $3 \times 3 = 9$ kinds of level-$3$ gems in this way.

1 100
100

200000 1000000000
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