#AT2023. C - Product

C - Product

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C - Product

Score : $300$ points

Problem Statement

We have $N$ bags.
Bag $i$ contains $L_i$ balls. The $j$-th ball $(1\leq j\leq L_i)$ in Bag $i$ has a positive integer $a_{i,j}$ written on it.

We will pick out one ball from each bag.
How many ways are there to pick the balls so that the product of the numbers written on the picked balls is $X$?

Here, we distinguish all balls, even with the same numbers written on them.

Constraints

  • $N \geq 2$
  • $L_i \geq 2$
  • The product of the numbers of balls in the bags is at most $10^5$: $\displaystyle\prod_{i=1}^{N}L_i \leq 10^5$.
  • $1 \leq a_{i,j} \leq 10^9$
  • $1 \leq X \leq 10^{18}$
  • All values in input are integers.

Input

Input is given from Standard Input in the following format:

NN XX

L1L_1 a1,1a_{1,1} a1,2a_{1,2} \ldots a1,L1a_{1,L_1}

L2L_2 a2,1a_{2,1} a2,2a_{2,2} \ldots a2,L2a_{2,L_2}

\vdots

LNL_N aN,1a_{N,1} aN,2a_{N,2} \ldots aN,LNa_{N,L_N}

Output

Print the answer.


2 40
3 1 8 4
2 10 5
2

When choosing the $3$-rd ball in Bag $1$ and $1$-st ball in Bag $2$, we have $a_{1,3} \times a_{2,1} = 4 \times 10 = 40$.
When choosing the $2$-nd ball in Bag $1$ and $2$-nd ball in Bag $2$, we have $a_{1,2} \times a_{2,2} = 8 \times 5 = 40$.
There are no other ways to make the product $40$, so the answer is $2$.


3 200
3 10 10 10
3 10 10 10
5 2 2 2 2 2
45

Note that we distinguish all balls, even with the same numbers written on them.


3 1000000000000000000
2 1000000000 1000000000
2 1000000000 1000000000
2 1000000000 1000000000
0

There may be no way to make the product $X$.