#AT1351. C - Switches

C - Switches

C - Switches

Score : $300$ points

Problem Statement

We have $N$ switches with "on" and "off" state, and $M$ bulbs. The switches are numbered $1$ to $N$, and the bulbs are numbered $1$ to $M$.

Bulb $i$ is connected to $k_i$ switches: Switch $s_{i1}$, $s_{i2}$, $...$, and $s_{ik_i}$. It is lighted when the number of switches that are "on" among these switches is congruent to $p_i$ modulo $2$.

How many combinations of "on" and "off" states of the switches light all the bulbs?

Constraints

  • $1 \leq N, M \leq 10$
  • $1 \leq k_i \leq N$
  • $1 \leq s_{ij} \leq N$
  • $s_{ia} \neq s_{ib} (a \neq b)$
  • $p_i$ is $0$ or $1$.
  • All values in input are integers.

Input

Input is given from Standard Input in the following format:

NN MM

k1k_1 s11s_{11} s12s_{12} ...... s1k1s_{1k_1}

::

kMk_M sM1s_{M1} sM2s_{M2} ...... sMkMs_{Mk_M}

p1p_1 p2p_2 ...... pMp_M

Output

Print the number of combinations of "on" and "off" states of the switches that light all the bulbs.


2 2
2 1 2
1 2
0 1
1
  • Bulb $1$ is lighted when there is an even number of switches that are "on" among the following: Switch $1$ and $2$.
  • Bulb $2$ is lighted when there is an odd number of switches that are "on" among the following: Switch $2$.

There are four possible combinations of states of (Switch $1$, Switch $2$): (on, on), (on, off), (off, on) and (off, off). Among them, only (on, on) lights all the bulbs, so we should print $1$.


2 3
2 1 2
1 1
1 2
0 0 1
0
  • Bulb $1$ is lighted when there is an even number of switches that are "on" among the following: Switch $1$ and $2$.
  • Bulb $2$ is lighted when there is an even number of switches that are "on" among the following: Switch $1$.
  • Bulb $3$ is lighted when there is an odd number of switches that are "on" among the following: Switch $2$.

Switch $1$ has to be "off" to light Bulb $2$ and Switch $2$ has to be "on" to light Bulb $3$, but then Bulb $1$ will not be lighted. Thus, there are no combinations of states of the switches that light all the bulbs, so we should print $0$.


5 2
3 1 2 5
2 2 3
1 0
8